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42 lines
1.0 KiB
Markdown
42 lines
1.0 KiB
Markdown
# LinearAllocator::Allocate
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```cpp
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void* Allocate(size_t size, size_t alignment = 8) override;
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```
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在缓冲区的当前位置顺序分配内存。每次分配都会将内部偏移量向前推进(对齐后)。如果剩余空间不足,则分配失败返回 `nullptr`。默认对齐值为 8 字节。
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**参数:**
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- `size` - 请求的字节数
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- `alignment` - 内存对齐要求,默认为 8 字节
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**返回:** 分配成功返回已对齐的指针,失败返回 `nullptr`
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**复杂度:** O(1)
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**示例:**
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```cpp
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#include <XCEngine/Memory/LinearAllocator.h>
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LinearAllocator allocator(1024);
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// 分配 256 字节(8 字节对齐)
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void* ptr1 = allocator.Allocate(256);
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// 分配 128 字节(16 字节对齐)
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void* ptr2 = allocator.Allocate(128, 16);
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// 分配 64 字节(默认 8 字节对齐)
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void* ptr3 = allocator.Allocate(64);
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// 检查是否成功
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if (!ptr1) {
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// 分配失败,缓冲区已满
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}
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```
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## 相关文档
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- [LinearAllocator 总览](linear-allocator.md) - 返回类总览
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